The probability of hitting a target by three marksmen is $\frac{1}{2}, \frac{1}{3},$ and $\frac{1}{4}$ respectively. If the probability that exactly two of them will hit the target is $\lambda$ and that at least two of them hit the target is $\mu,$ then $\lambda + \mu$ is equal to :-

  • A
    $\frac{13}{24}$
  • B
    $\frac{6}{24}$
  • C
    $\frac{7}{24}$
  • D
    None

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